Question

tìm x

a,134:(x-3)=35+160:5

b,[(10-x).2+]:3-2=3

tl nhớ kb vs mk na

Answer 1

a, 134: [x-3] = 35 + 160: 5

134 : [x-3] = 35 + 32

134 : [x-3] = 67

x - 3 = 134: 67 

x-3 = 2

x = 2 + 3

x = 5

Bài b bạn ghi lại đề nha

Answer 2

a,134:(x-3)=35+160:5

=> 134:(x-3)=35+32

=> 134:(x-3)= 67

=> x - 3 = 134 : 67

=> x-3 = 2

=> x = 2 + 3 = 5

b,[(10-x).2]:3-2=3

=> [(10-x).2]:3 = 3+2

=> [(10-x).2]:3 = 5

=> (10 -x) . 2 = 5.3

=> (10 - x).2 = 15

=> 10-x = 15: 2

=> 10 - x =7,5

=> x = 10 - 7,5 = 2,5

Answer 3

a,134:(x-3)=35+160:5

134:(x-3)=35+32

134:(x-3)=67

      (x-3)=134:67

       x-3 =2

          x =2+3

          x =5

b,[(10-x).2+]:3-2=3

[(10-x).2+]:3=3+2

[(10-x).2+]:3=5

(10-x).2+=5.3

(10-x).2+=15

(10-x) =15:2

10-x=7,4

    x=10-7,4

    x=2,6