\(\left(3x-4\right)\left(x-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}3x-4=0\\x-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}3x-4=0\Rightarrow3x=4\Rightarrow x=\frac{4}{3}\\x-1=0\Rightarrow x=1\end{cases}}\)
Vậy x bằng \(\frac{4}{3}\) và x = 1
\(\left(3x-4\right)\left(x-1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=1\end{cases}}\)
Ta có : (3x - 4)(x - 1) = 0
\(\Leftrightarrow\orbr{\begin{cases}3x-4=0\\x-1=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}3x=4\\x=1\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{4}{3}\\x=1\end{cases}}\)
a) (3x - 4 ) (x-1) = 0
TH1 : => 3x -4 = 0 => 3x = 0+ 4 => 3x = 4 :3 = 4/3
TH2: => x - 4 = 0 => x= 0+4 = 4
Vây x = 4/3 hoăc x= 4
c) x ^17 =x
=> x = 1
Ta có (3x-4 )(x-1)=0
<=>\(\orbr{\begin{cases}3x-4=0\\x-1=0\end{cases}}\)
<=>\(\orbr{\begin{cases}3x=4\\x=1\end{cases}}\)
<=>\(\orbr{\begin{cases}x=\frac{4}{3}\\x=1\end{cases}}\)
Khi(3x-4)-(x-1)=0
<=>[3x-4]=0
<=>[x-1]=0
Vây X=\(\frac{4}{3}\)
X=1