Tìm x
a) 17 + 33 : ( 2 . x - 1 ) = 20
33 :( 2 . x - 1 )= 20 - 17
33 :( 2 . x - 1 ) = 3
2 . x - 1 = 33 : 3
2 . x - 1 = 11
2 . x = 11 - 1 = 10
x = 10 : 2
x = 5
b) 25 - [ ( 2 . x + 5 ) . 7 - 15 ] : 5 = 21
[ ( 2 . x + 5 ) . 7 - 15 ] : 5 = 25 - 21
[ ( 2 . x + 5 ) . 7 - 15 ] : 5 = 4
( 2 . x + 5 ) . 7 - 15 = 5 x 4
( 2 . x + 5 ) . 7 - 15 = 20
( 2 . x + 5 ) . 7 = 20 + 15
( 2 . x + 5 ) . 7 = 35
2 . x + 5 = 35 : 7
2 . x + 5 = 5
2 . x = 5 - 5
2 . x = 0
x = 0
hok tốt
a) \(17+33:\left(2x-1\right)=20\)
\(\Rightarrow33:\left(2x-1\right)=20-17\)
\(\Rightarrow33:\left(2x-1\right)=3\)
\(\Rightarrow2x-1=33:3\)
\(\Rightarrow2x-1=11\)
\(\Rightarrow2x=11+1\)
\(\Rightarrow2x=12\)
\(\Rightarrow x=12:2\)
\(\Rightarrow x=6\)
Vậy x = 6
b) \(25-\left[\left(2x+5\right)\times7-15\right]:5=21\)
\(\Rightarrow\left[\left(2x+5\right)\times7-15\right]:5=25-21\)
\(\Rightarrow\left[\left(2x+5\right)\times7-15\right]:5=4\)
\(\Rightarrow\left(2x+5\right)\times7-15=4\times5\)
\(\Rightarrow\left(2x+5\right)\times7-15=20\)
\(\Rightarrow\left(2x+5\right)\times7=20+15\)
\(\Rightarrow\left(2x+5\right)\times7=35\)
\(\Rightarrow2x+5=35:7\)
\(\Rightarrow2x+5=5\)
\(\Rightarrow2x=5-5\)
\(\Rightarrow2x=0\)
\(\Rightarrow x=0:2\)
\(\Rightarrow x=0\)
Vậy x = 0
_Chúc bạn học tốt_
a ) 17 + 33 : ( 2 . x - 1 ) = 20
33 : ( 2x - 1 ) = 20 - 17
33 : ( 2x - 1 ) = 3
2x - 1 = 33 : 3
2x - 1 = 11
2x = 11 - 1
2x = 10
x = 10 : 2
x = 5
Vậy x = 5
b) 25 - [ ( 2x + 5 ) . 7 - 15 ] : 5 = 21
[ ( 2x + 5 ) . 7 - 15 ] : 5 = 25 - 21
[ ( 2x + 5 ) . 7 - 15 ] : 5 = 4
( 2x + 5 ) . 7 - 15 = 4 x 5
( 2x + 5 ) . 7 - 15 = 20
( 2x + 5 ) . 7 = 20 + 15
( 2x + 5 ) . 7 = 35
2x + 5 = 35 : 7
2x + 5 = 5
2x = 5 - 5
2x = 0
x = 0 : 2
x = 0
Vậy x = 0
