a, (1-3x)3=(-2)3
=>1-3x=( - 2)
3x = 1 - ( - 2 )
3x = 3
x= 3:3
=> x=1
b, (5x + 1)2 = 72
=> 5x +1 = 7
5x =7 - 1
5x= 6
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a) 1-3x) ^ 3 = -8
=> (1-3x) = -2
=> 3x = 3
=> x = 1
b) (5x+1)^2 = 49
=> 5x+1 = 7
=> 5x = 6
=> x = 5/6
a) \(\left(1-3x\right)^3=-8\)
\(\left(1-3x\right)^3=\left(-2\right)^3\)
\(\Rightarrow1-3x=-2\)
\(3x=1-\left(-2\right)\)
\(3x=3\)
\(x=3:3\)
\(x=1\)
b) \(\left(5x+1\right)^2=49\)
\(\left(5x+1\right)=7^2=\left(-7\right)^2\)
\(\Rightarrow5x+1=7\)hoặc \(5x+1=-7\)
Nếu \(5x+1=7\)\(5x=7-1=6\)
\(x=\frac{6}{5}=1\frac{1}{5}\)
Nếu \(5x+1=-7\)\(5x=-7-1=-8\)
\(x=-\frac{8}{5}=-1\frac{3}{5}\)
Vậy \(x=1\frac{1}{5}\)hoặc \(x=-1\frac{3}{5}\)