a) 7x+2 + 2.7x-1 = 345
7x-1 . 73 + 2.7x-1 = 345
7x-1.(343+2) = 345
7x-1. 345=345
=> 7x-1=1
=> 7x-1=70
=> x-1 =0
x=1
b)\(\frac{1}{2}\).2x + 2x+2= 28+25
\(\frac{1}{2}\).2x + 2x . 22 = 288
2x . ( \(\frac{1}{2}\)+ 4)= 288
2x . \(\frac{9}{2}\)=288
=>2x=64
2x= 26
=>x=6
c)2.3x +3x-1 = 7.( 32+2.62)
2.3x-1.31 + 3x-1 = 567
3x-1.(6+1)=567
3x-1.7=567
=>3x-1= 81
3x-1=34
=>x-1=4
x=5
2.3x+3x-1=7.(32+2.62)
7x+22.7x-1=345
tính:
\(a.9^x:3^x=3^7\)
b.\(\frac{1}{2}.2^x+2^{x+2}=2^8+2^5\)
c\(^{7^{x+2}+2.7^{x-1}=345}\)
d \(\left(\frac{1}{2}-\frac{1}{3}\right).6^x+6^{x+2}=6^7+6^4\)
tìm các số nguyên n sao cho
\(\left(\frac{4}{9}\right)^n=\left(\frac{2}{3}\right)^5\)
Tìm X
\(7^{X+2}+2.7^{X-1}=345\)
Tìm x biết :
a)\(3^{-2}.3^2.27^x=\frac{1}{3}\)
b)\(7^{x+2}+2.7^{x-1}=345\)
c)\(\left(2x-1\right)^6=\left(2x-1\right)^8\)
\(2^{x+2}-2^x=96\)
.\(7^{x+2}+2.7^{x-1}=345\)
\(\left(2x-1\right)^6=\left(2x-1\right)^8\)
Tìm x, biết:
b. \(-\frac{7}{9}-\left(\frac{1}{3}-x\right)^2:2=-1\)
h. \([2^2+\left(2^2\right)^3].x+3^4.x=2^2.3^7+1\)
Bài 1 : Tìm x biết :
a, \(\left|\frac{3}{2}x+\frac{1}{2}\right|=\left|4x-1\right|\)
b, \(\left|\frac{5}{4}x-\frac{7}{2}\right|-\left|\frac{5}{8}x+\frac{3}{5}\right|=0\)
c,\(\left|\frac{7}{5}x+\frac{2}{3}\right|=\left|\frac{4}{3}x-\frac{1}{4}\right|\)
Bài 2 : Tìm x biết :
a, | 2x - 5 | = x +1
b, | 3x - 2 | -1 = x
c, | 3x - 7 | = 2x + 1
d, | 2x-1 | +1 = x
Tìm x biết
a) (8-5x).(x+2)+4.(x-2).(x+1)+2.(x-2).(x+2)=0
b)\(\left(-\frac{2}{5}+x\right):\frac{7}{9}+\left(-\frac{3}{5}+\frac{5}{6}\right):\frac{7}{9}=0\)
c)\(1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=1\frac{2003}{2004}\)
Tính giá trị của biểu thức:
1)\(A=\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^43^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
2) CHo x , y , z khác 0 và x-y-z=0 Tính \(B=\left(1-\frac{z}{x}\right)\left(1-\frac{x}{z}\right)\left(1+\frac{y}{z}\right)\)
