Question

Tìm \(x\)

\(71+65\)x 4= \(\frac{x+140}{x}\)+ 260

Answer 1

\(71+65\cdot4=\frac{x+140}{x}+260\)

\(\Rightarrow71+260=\frac{x}{x}+\frac{140}{x}+260\)

\(\Rightarrow71=1+\frac{140}{x}\)

\(\Rightarrow\frac{140}{x}=70\)

\(\Rightarrow x=2\)

Answer 2

71+65*4=x+140 +260

                   x

=>71+260=   x   +  140  +260

                     x          x 

=>71=1+   140   

                   x

=> 71-1 =    140   

                      x

=> 70=140:x

=>x=140:70=2

Answer 3

71 + 65 x 4 = x + 140/x + 260

331 = x/x + 140/x + 260

331 = 1 + 140/x + 260

=> 331 - 1  - 260 = 140/x

70 = 140/x

x = 140 : 70

x = 2

Answer 4

\(71+65\times4=\frac{x+140}{x}+260\)

\(\Rightarrow71+260=\frac{140+x}{x}+260\)

\(\Rightarrow331=\frac{140+x}{x}+260\)

\(\Rightarrow\frac{140+x}{x}=331-260\)

\(\Rightarrow\frac{140+x}{x}=71\)

\(\Rightarrow140+x=71x\)

\(\Rightarrow71x-x=140\)

\(\Rightarrow70x=140\)

\(\Rightarrow x=140:70\)

\(\Rightarrow x=2\)

Vậy  \(x=2\)

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