\(5x\left(x-2018\right)-x+2018=0\)
\(5x\left(x-2018\right)-\left(x-2018\right)=0\)
\(\left(x-2018\right)\left(5x-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-2018=0\\5x-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2018\\x=\frac{1}{5}\end{cases}}\)
Vậy.........
x = 2018
x = 1/5
t i c k nha
\(5x\left(x-2018\right)-x+2018=0\)
\(\Leftrightarrow5x\left(x-2018\right)-\left(x-2018\right)=0\)
\(\Leftrightarrow\left(x-2018\right)\left(5x-1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-2018=0\\5x-1=0\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=2018\\x=\frac{1}{5}\end{cases}}\)