Question

Tìm x....

\(3^{2x+4}\):  \(3^{x+2}\)= 81

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Thank trước. Mn kb vs mik nhé

Answer 1

\(3^{2x+4}:3^{x+1}=81\)

\(3^{2x+4-x-1}=3^4\)

\(3^{x+3}=3^4\)

\(\Rightarrow x+3=4\)

\(\Rightarrow x=1\)

Answer 2

\(3^{2x+4}:3^{x+2}=81\)

\(\Rightarrow3^{2x+4-x-2}=3^4\)

\(\Rightarrow3^{x+2}=3^4\)

\(\Rightarrow x+2=4\)

\(\Rightarrow x=4-2=2\)

Answer 3

Nhầm đề :v

\(3^{2x+4}:3^{x+2}=81\)

\(3^{2x+4-x-2}=3^4\)

\(3^{x+2}=3^4\)

\(\Rightarrow x+2=4\)

\(\Rightarrow x=2\)

Answer 4

3²ⁿ⁺⁴:3^x+1 =81

-> 3²ⁿ⁺⁴:3^x+1=3⁴

^-> 2n+4-x-1=4

-> x+3=4

-> x=1

Vậy x=1

Answer 5

\(3^{2x+4}\):\(3^{x+2}\)=81

\(3^{\left(2x+4\right)-\left(x+2\right)}\)=81

\(3^{2x+4-x-2}\)=81

\(3^{\left(2x-x\right)+\left(4-2\right)}\)=81

\(3^{x+2}\)=81

\(3^{x+2}\)=\(3^4\)

\(x+2=4\)

\(x=4-2\)

\(x=2\)