(3-x)^10x:(3-x)^20=1(x ko =3)
(3-x)10x ÷ (3-x)20 =1 với x khác 3 tìm x
a ) (3 - x)10x : (3 - x)20 = 1 ( x khác 3 )
[3-x] 10x: [3-x] 20 = 1
TÌm x
a,(3-x)^ 10x : (3-x)^20=1
b, 2^x-1+ 3^3= 5^2+2*5
tim x 4.(x- 3)- 5.(2- x )= 10x- 15
tim x biet: (2x-3)^10x=(3-2x)^100
c/ [ 3 - x]10x : [3 - x]20=1
d/ [ x - 6 ]3 = [x - 6]2
(3-x)^10x : (3-x)^20=1