Question

tìm x

2^x.4=128

(2^x+1)³=125

2^x-15=17

Answer 1

2^x.4=128

=> 2^x=128:4

=> 2^x=32

=> 2^x=2⁵

=> x=5

(2^x+1)³=125

=>(2^x+1)³=5³

=>2^x+1=5

=>2^x=5-1

=>2^x=4

=>2^x=2²

=>x=2

2^x-15=17

=>2^x=17+15

=>2^x=32

=>2^x=2⁵

=>x=5

Answer 2

a) x=5

b) x=2

c) x=5

Answer 3

x = 5 

 x= 2

x = 5 

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Answer 4

2^x.4=128

2^x = 128:4

2^x = 32

2^x = 2⁵

=> x = 5

(2^x+1)³ = 125 = 5³

=> 2^x +1 =5 

2^x = 5-1 

2^x =4=2²

=> x =2 

2^x - 15 = 17

2^x = 17 - 15

2^x = 2 = 2¹

=> x = 1

Answer 5

a) 2^x.4=128

2^x=128:4

2^x=32

2^x=2⁵

Vậy x=5

b) x=2

c) x=5