Ta có:\(\left(2x-\dfrac{1}{2}\right)\left(\dfrac{5}{4}-3x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}2x-\dfrac{1}{2}=0\\\dfrac{5}{4}-3x=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=\dfrac{1}{2}\\3x=\dfrac{5}{4}\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=\dfrac{5}{12}\end{matrix}\right.\)
Vậy \(\left[{}\begin{matrix}x=\dfrac{1}{4}\\x=\dfrac{5}{12}\end{matrix}\right.\)