Tìm x
\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
Tìm x:\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
Tìm x biết:
2x-1+5.2x-1=\(\frac{7}{32}\)
tìm x : 2x-1 +5.2x-2=\(\frac{7}{32}\)
Tìm x biết:
a. \(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
b.\(\left|x\left(x^2-\frac{5}{4}\right)\right|=x\)
2\(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
tìm x , biết
a, \(2^{x-1}+5.2^{x-2}=\frac{7}{32}\)
b, 2005 = /x - 4 | + |x - 10 | + |x +101 | + |x + 990 |+ |x + 1000 | (x thuộc Z )
2x-1+5.2x-2=\(\frac{7}{32}\)
tìm X, 2(x-1)+5.2(x-2)= 7/32