Question

Tìm x:

(2x—1) (x+2) — 3 (x+2) = 0

Giúp mình vs, mai mình nộp mất cảm ơn nhiều ạ

Answer 1

\(2x-1\left(x+2\right)-3\left(x+2\right)=0\)

\(\Rightarrow\left(2x-4\right)\left(x+2\right)=0\)

\(\Rightarrow\orbr{\begin{cases}2x-4=0\\x+2=0\end{cases}\Rightarrow\orbr{\begin{cases}x=2\\x=-2\end{cases}}}\)

Answer 2

(2x-1)(x+2)-3(x+2)=0

<=>2x²+3x-2-3x-6=0

<=>2x²-8=0

<=>2(x²-4)=0

<=>x²-4=0

<=>(x+2)(x-2)=0

=>\(\orbr{\begin{cases}x+2=0\\x-2=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-2\\x=2\end{cases}}}\)

Vậy...

Answer 3

(2x-1)(x+2)-3(x+2)=0

(x+2)[(2x-1)-3]=0

(x+2)(2x-1-3)=0

(x+2)(2x-4)=0

TH1: x+2=0 nên x=-2

TH2: 2x-4=0 nên 2x=4 nên x=2

vậy x=-2 hoặc x=2

Answer 4

<=> \(\left(x+2\right)\left(2x-1-3\right)=0\)

<=>\(\left(x+2\right)\left(2x-4\right)=0\)

<=>\(2\left(x+2\right)\left(x-2\right)=0\)

<=>\(\orbr{\begin{cases}x+2=0\\x-2=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-2\\x=2\end{cases}}}\)

Vay phuong trinh co tap nghiem S={-2;2)

Study well

Answer 5

Vì (2x -1) (x+2) - 3 (x + 2) = 0

=> ( 2x -1) (x + 2) = 3 ( x+ 2)

=> ( 2x -1) = 3

=> 2x = 4

x=2

Answer 6

(2x - 1)(x + 2) - 3(x + 2) = 0

(x + 2)[2x - 1 - (3)] = 0

x = -+2