5(x+3)=225-102
x+3=123/5
x=123/5-3
x=108/5
225-5(x+3)=102
=>225-5x-15=102
=>210-5x=102
=>5x=108
=>x=\(\frac{108}{5}\)
225 - 5(x + 3) = 102
5(x + 3) = 225 - 102
5(x + 3) = 123
x + 3 = 123/5
x = 123/5 - 3
x = 108/5
\(255-5.\left(x+3\right)=102\)
\(5.\left(x+3\right)=255-102\)
\(5.\left(x+3\right)=153\)
\(x+3=\frac{153}{5}\)
\(x=\frac{153}{5}-3\)
\(x=\frac{138}{5}\)
