\(2|3x-1|=4+|3x-1|\)
\(2|3x-1|-|3x-1|=4\)
\(|3x-1|=4\)
\(\orbr{\begin{cases}3x-1=4\\3x-1=-4\end{cases}}\)
\(\orbr{\begin{cases}3x=4+1\\3x=-4+1\end{cases}}\)
\(\orbr{\begin{cases}3x=5\\3x=-3\end{cases}}\)
\(\orbr{\orbr{\begin{cases}x=\frac{5}{3}\\x=-1\end{cases}}}\)
Vậy x =\(\frac{5}{3}\)hoặc x=\(-1\)