\(17-2\left(2x-3\right)=3\)
\(17-4x+6=3\)
\(23-4x=3\)
\(4x=23-3=20\)
\(x=\frac{20}{4}=5\)
17 - 2.(2x-3) =3
<=> -2(2x -3) =-14
<=> 2x -3=7
<=>2x =10
<=>x=5
17 - 2 . (2x - 3) = 3
2 . (2x - 3) = 17 - 3
2 . (2x - 3) = 14
2x - 3 = 14 : 2
2x - 3 = 7
2x = 7 + 3
2x = 10
x = 10 : 2
x = 5
Vậy x = 5
ta có: \(\Leftrightarrow\)17-4x+6=3
\(\Leftrightarrow\)17+6-3=4x
\(\Leftrightarrow\)4x=20
\(\Leftrightarrow\)x=5
17-2.(2x-3)=3
2.(2x-3)=17-3
2.(2x-3)=14
2x-3=14:2
2x-3=7
2x=7+3
2x=10
x=10:2
x=5
17-2.(2x-3)=3
2.(2x-3)=17-3
2.(2x-3)=14
2x-3=14/2
2x-3=7
2x =7+3
2x =10
x =10/2
x =5
17-2(2x-3)=3
17-4x+6=3
23-4x=3
4x=23-3=20
X=20/4=5
