Question

tìm x

(12x-5)(4x-1)+(3x-7)(1-16x)=81

xin mk với đang vội

 

Answer 1

(12x-5)(4x-1)+(3x-7)(1-16x)=81

48x^2-12x-20x+5+3x-48x^2-7+112x=81

83x-2=81

83x=83

x=1

Answer 2

(12x-5)(4x-1)+(3x-7)(1-16x)=81
12x ( 4x- 1) - 5(4x-1) + 3x(1-16x) -7(1-16x) =81
12x . 4x -12x - 20x + 5 + 3x - 3x. 16x - 7 + 7.16x = 81
48x^2 -12x - 20x + 5 + 3x - 48x^2 - 7 + 112x = 81
(48x^2 - 48x^2) + (112x - 12x - 20x +3x) - ( 7 - 5) =81
83x = 81 + 2
83x =83
x=1

ht nha bạn

Answer 3

Rút gọn vế trái:

VT = (12x – 5)(4x – 1) + (3x – 7)(1 – 16x)

     = 12x.(4x – 1) + (–5).(4x – 1) + 3x.(1 – 16x) + (–7).(1 – 16x)

     = 12x.4x+ 12x.(–1) + (–5).4x + (–5).(–1) + 3x.1 + 3x.(–16x) + (–7).1 + (–7).(–16x)

     = 48x2 – 12x – 20x + 5 + 3x – 48x2 – 7 + 112x

     = (48x2 – 48x2) + (– 12x – 20x + 3x + 112x) + (5 – 7)

     = 83x – 2

Vậy ta có:

83x – 2 = 81

       83x = 81 + 2

       83x = 83

           x = 83 : 83

           x = 1.

Answer 4

X=1 NHA  BẠN

Answer 5

(12x-5)(4x-1)+(3x-7)(1-16x)=81

<=>48x^2-12x-20x+5+3x-48x^2-7+112x=81

<=>-32x+115x=81+2

<=>81x=81

<=>x=1     ^^