\(1+2+3+4+...+x=210\)
Ta có : \(\frac{\left(1+x\right).x}{2}=210\)
\(\Leftrightarrow\left(1+x\right).x=210.2\)
\(\Leftrightarrow\left(1+x\right).x=420\)
\(\Leftrightarrow\left(1+x\right).x=21.20\)
\(\Rightarrow x=20\)
Ta có:1+2+3+...+x=[x.(x+1)] : 2=2010
=>x.(x+1)=2010.2
=>x.(x+1)=420=20.21
=>x=20
Ủng hộ mik nhé!
x = 20 nha bạn
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Ta có :
\(\frac{\left(x+1\right)x}{2}=210\)
\(\Leftrightarrow\left(x+1\right)x=420\)
\(\Leftrightarrow21.20=420\)
Vậy x = 20
Đ/S : ...