\(\frac{1}{17}+\frac{1}{2}=3x-\frac{3}{2}\)
\(\frac{2}{34}+\frac{17}{34}=3x-\frac{3}{2}\)
\(\frac{19}{34}=3x-\frac{3}{2}\)
\(3x=\frac{19}{34}+\frac{3}{2}=\frac{19}{34}+\frac{51}{34}\)
\(3x=\frac{70}{34}\)
\(\Rightarrow x=\frac{70}{34}\div3=\frac{70}{34\cdot3}=\frac{35}{51}\)
\(\Rightarrow x=-\frac{16}{17}\div3=-\frac{16}{51}\)
\(\frac{1}{17}+\frac{1}{2}=3x-\frac{3}{2}\)
\(\frac{19}{34}=3x-\frac{3}{2}\)
\(\frac{35}{17}=3x\)
\(\frac{35}{17}\div3=x\)
\(\frac{35}{51}=x\)
Vậy ...
1/17 + 1/2 = 3x - 3/2
19/34 = 3x - 3/2
3x - 3/2 = 19/34
3x = 19/34 + 3/2
3x = 34/17
x = 34/17 : 3
x = 2/3
1/7+1/2=3x-3/2
1/7+1/2+3/2=3x
9/14+3/2=3x
15/7=3x
15/7 : 3=x
5/7=x
