\(\frac{x-2}{x-1}=\frac{x+4}{x-7}\)
<=>(x-2)(x-7)=(x-1)(x+4)
<=>x2-9x+14=x2+3x-4
<=>x2-9x-x2-3x=-4-14
<=>-12x=-18
<=>x=\(\frac{3}{2}\)
2,\(\frac{x+4}{20}=\frac{5}{x+4}\)
<=>(x+4)2=100
<=>x2+8x+16=100
<=>x2+8x-84=0
<=>x2+14x-6x-84=0
<=>x(x+14)-6(x+14)=0
<=>(x-6)(x+14)=0
<=>\(\orbr{\begin{cases}x-6=0\\x+14=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=6\\x=-14\end{cases}}}\)