Question

 tìm x; y

\(4x^2+y^2-4x+10y+26=0\)0

Answer 1

          \(4x^2+y^2-4x+10y+26=0\)

\(\Leftrightarrow\)\(\left(4x^2-4x+1\right)+\left(y^2+10y+25\right)=0\)

\(\Leftrightarrow\)\(\left(2x-1\right)^2+\left(y+5\right)^2=0\)

\(\Leftrightarrow\)\(\hept{\begin{cases}2x-1=0\\y+5=0\end{cases}}\)

\(\Leftrightarrow\)\(\hept{\begin{cases}x=\frac{1}{2}\\y=-5\end{cases}}\)

Vậy..