Question

Tìm x, y, z \(\in\)Z, biết:

\(\frac{x}{-10}=\frac{-7}{y}=\frac{z}{-6}=\frac{-4}{8}\)

Answer 1

4/8 =x/−10 =−7/y =z/−6

⇒-4/8 =x/−10 ⇒x=4·(−10)/8 =−5⁽¹⁾

⇒−5/10 =−7/y ⇒y=−10·(−7)/−5 =−14⁽²⁾

⇒−7/14 =z/−6 ⇒z=−7·(−6)/−14 =−3⁽³⁾

Từ (1);(2);(3) . Ta có -4/8 =5/-10 =−7/14 =3/-6 

Answer 2

\(\frac{x}{-10}=\frac{-7}{y}=\frac{z}{-6}=\frac{-4}{8}\)

Ta có ; 

\(\frac{x}{-10}=\frac{-4}{8}\Leftrightarrow\frac{8x}{-80}=\frac{40}{-80}\Leftrightarrow8x=40\Leftrightarrow x=5\)

\(\frac{-7}{y}=\frac{-4}{8}\Leftrightarrow\frac{-56}{8y}=\frac{-4y}{8y}\Leftrightarrow-56=-4y\Leftrightarrow y=14\)

\(\frac{z}{-6}=\frac{-4}{8}\Leftrightarrow\frac{8z}{-48}=\frac{24}{-48}\Leftrightarrow8z=24\Leftrightarrow x=3\)