Các câu hỏi tương tự
x/-2=9/y=3-2z/5
x+z=0
Tim y
tim x;y;z biet x(x+y+z)=2; y(x+y+z)=25; z(x+y+z)=-2; x>0
cho x/-2=9/x=(3-2z)/5 va x+z=0. Tim y
bai 1: Tim x biet
\(\hept{\begin{cases}x-y=\frac{3}{10}\\y\left(x-y\right)=-\frac{3}{50}\end{cases}}\)
bai 2: Tim x, y biet:
x+\(\left(-\frac{31}{12}\right)^2\)=\(\left(\frac{49}{12}\right)^2\)-x=y2
Bai 9: Tim x,y,z biet:
(x-1)2+(x+y)2+(xy-z)2=0
Tim x, y, z biet
a ) |x-3,5|+ |x+5|=0
b) |x-1| + (y+1)^2 + |z-1|=0
c) ( x-1/3)^2 + (y-2)^2+ (z-1)^2 be hon hoac bang 0
d)(x-z)^2+ (y+x)^2 + (z+1/4)^2 =0
Cac ban giup minh voi minh can gap lam
Tim cac so x,y,z biet x/y=9/7; y/2=7/3 va x-y+z=-15
tim x;y;z biet |x+3/7|+ |y-4/9|+ |z+5/11|=0
tim x, y, z
a) x/y=-6/9 va x-y=30
b)x/5=y/4, z/5=y/7 va 2*x+3*y-z=106
c)x/5=y/4=z/7 va x+2*y+z=40
tim cac so x,y,z thuoc Q biet rang (x+y):(5-z):(y+z):(y+9)=3:1:2:5