\(4x\left(x-1\right)+3\sqrt{2}\left(x-1\right)=0\)
\(\Rightarrow\left(4x+3\sqrt{2}\right)\left(x-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}4x+3\sqrt{2}=0\\x-1=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}4x=-3\sqrt{2}\Rightarrow x=\frac{-3\sqrt{2}}{4}\\x=1\end{cases}}\)
Vậy ....
Chắc sai =))
\(4x\left(x-1\right)+3\sqrt{2}\left(1-x\right)=0\)
\(\Leftrightarrow4x^2-4x+3\sqrt{2}-3\sqrt{2}x=0\)
\(\Leftrightarrow4x^2-\left(4+3\sqrt{x}\right)x+3\sqrt{2}=0\)
Ta có: \(\Delta=\left(4+\sqrt{3}\right)^2-4.4.3\sqrt{2}=34-24\sqrt{2}\)
Vậy pt có 2 nghiệm:
\(x_1=\frac{4+3\sqrt{2}+34-24\sqrt{2}}{8}=\frac{38-21\sqrt{2}}{8}\)
\(x_2=\frac{4+3\sqrt{2}-34+24\sqrt{2}}{8}=\frac{-30+27\sqrt{2}}{8}\)
Làm ko kiểm lại, )):
\(4x\left(x-1\right)+3\sqrt{2}\left(1-x\right)=0\)
\(\Leftrightarrow4x\left(x-1\right)-3\sqrt{2}\left(x-1\right)=0\)
\(\Leftrightarrow\left(4x-3\sqrt{2}\right)\left(x-1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}4x-3\sqrt{2}=0\\x-1=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{3\sqrt{2}}{4}\\x=1\end{cases}}\)
\(4x\left(x-1\right)+3\sqrt{2}\left(1-x\right)=0\)
\(\Leftrightarrow-4x\left(1-x\right)+3\sqrt{2}\left(1-x\right)=0\)
\(\Leftrightarrow\left(1-x\right)\left(3\sqrt{2}-4x\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}1-x=0\\3\sqrt{2}-4x=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=1\\x=\frac{3\sqrt{2}}{4}\end{cases}}}\)
