Ta có \(\left(2x-1\right)^{2008}\)\(\ge0\)với mọi x
\(\left(y-\frac{2}{5}\right)^{2008}\ge0\)với mọi y
|x+y-z| \(\ge\)0
Suy ra 2x-1=0 nên x=\(\frac{1}{2}\)
y-\(\frac{2}{5}\)=0 nên y=\(\frac{2}{5}\)
và x+y-z=0 hay \(\frac{1}{2}+\frac{2}{5}\)-z=0 suy ra z=\(\frac{9}{10}\)
tìm x,y,z biết: (2x-1)^2008+(y-2/5)^2008+| x+y+z|=0
tìm x,y,z thuộc N,biết :
a)A=(3x-5)^2006+(y^2-1)^2008+(x-z)^2100=0
b)B=(2x-1)^2008+(y-2:5)^2008+/x+y-z/=0
Tìm x, y, z biết: (2x-1)^2008+(y-2/5)^2008+|x+y-z|=0
Tìm x, y, z biết:
\(\left(2x-1\right)^{2008}+\left(y-\frac{2}{5}\right)^{2008}+\)I x + y + z I =0
Tìm x y z biết
\(\left(2x-1\right)^{2008}+\left(y-\frac{2}{5}\right)^{2008}+\left|x+y-z\right|=0\)
tìm x,y,z biết: (2x-1)^2008+(y-2/5)^2008+| x+y+z|=0
giúp với
Tìm x; y; z :
a) \(2009-\left|x-2009\right|=x\)
b) \(\left(2x-1\right)^{2008}+\left(y-\dfrac{2}{5}\right)^{2008}+\left|x+y-z\right|=0\)
Tìm x,y,z biết :
\(\left(2x-1\right)^{2008}+\left(y-\frac{2}{5}\right)^{2008}+\left|x+y-z\right|=0\)
tìm xyz
(2x-1)^2008+(y-2/5)^2008+\x+y+z\=0
