xy+x+y+1=-3
x(y+1)+y+1=-3
=>(y+1)(x+1)=-3
=> y+1 ;x+1 thuộc Ư(3)={ \(\pm1;\pm3\)}
th1: y+1=-1;x+1=3
y+1=-1
=>y=-2
x+1=3
=>x=2
th2: y+1=1;x+1=-3
y+1=1
=> y=0
x+1=-3
=>x=-4
vậy....
xy+x+y+1=-3
x(y+1)+y+1=-3
=>(y+1)(x+1)=-3
=> y+1 ;x+1 thuộc Ư(3)={ \(\pm1;\pm3\)}
th1: y+1=-1;x+1=3
y+1=-1
=>y=-2
x+1=3
=>x=2
th2: y+1=1;x+1=-3
y+1=1
=> y=0
x+1=-3
=>x=-4
vậy....
tim x , y thuoc z : (x+3).(y-1)=3
tim x,y thuoc Z biết (x-1)y=3
1 )Tim x, y thuoc Z
x + y = x.y
2) Tim x thuoc Z
(x + 1)+(x+3)+(x+5)+...+(x+99)=0(x-3)+(x-2)+(x-1)+...+10+11=11-12(x-5)+7(3-x)=530(x+2)-6(x-5)-24x=100tim x;y thuoc Z: (x-3)(2y+1)=7
Tim x,y thuoc Z
(x-3).(2y+1)=7
(x-3)*(2y+1)=7
Tim x,y thuoc Z
Tim x, y,z thuoc Z biết xy+1=z
x-1/9+1/3=1/y+2
x/2+y/3=x+y/2+3
Tim x;y thuoc z
Help me!
cac ban oi giup minh voi
1.tim a,b thuoc Z,biet:a.(2b-3)=-6
2.cho x,y thuoc Z thoa man x mu 2 +y mu 2 chia het cho 3.chung to x va y chia het cho 3.