Question

Tìm x ,y \(\in\) N biết :

a )2^x+1 . 3^y = 12^x

b ) 10^x : 5^y = 20^y

c) 2^x = 4^y-1 và 27^y = 3^{x +8}

Answer 1

a) \(2^{x+1}\cdot3^y=12^x\Leftrightarrow2^{x+1}\cdot3^y=2^{2x}\cdot3^x\)

\(\Rightarrow\left\{{}\begin{matrix}x+1=2x\\y=x\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=1\\y=1\end{matrix}\right.\)

b) \(10^x:5^y=20^y\Leftrightarrow20^y\cdot5^y=10^x\Leftrightarrow\left(20\cdot5\right)^y=10^x\Leftrightarrow100^y=10^x\Leftrightarrow10^{2y}=10^x\Leftrightarrow2y=x\)

c) \(\left\{{}\begin{matrix}2^x=4^{y-1}\\27^y=3^{x+8}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}2^x=2^{2y-2}\\3^{3y}=3^{x+8}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=2y-2\\3y=x+8\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x=2y-2\\3y=2y-2+8\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=10\\y=6\end{matrix}\right.\)