x+y+xy+1=0 => y+x(y+1)+1=0 => (y+1)+x(y+1)=0 => (x+1)(y+1)=0 => x=-1 thì y bất kì còn y = -1 thì x bất kì
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x+y+xy+1=0 => y+x(y+1)+1=0 => (y+1)+x(y+1)=0 => (x+1)(y+1)=0 => x=-1 thì y bất kì còn y = -1 thì x bất kì
tim x y biet x+y+xy+1=0
tim x y biet x+y+xy+1=0
tim x y biet x+y+xy+1=0
tim x y biet x+y+xy+1=0
tim x y biet x+y+xy+1=0
tim x y biet x+y+xy+1=0
tim x y biet x+y+xy+1=0
tim xy biet (x-0,2)^10+(y+3,1)=0
bai 1: Tim x biet
\(\hept{\begin{cases}x-y=\frac{3}{10}\\y\left(x-y\right)=-\frac{3}{50}\end{cases}}\)
bai 2: Tim x, y biet:
x+\(\left(-\frac{31}{12}\right)^2\)=\(\left(\frac{49}{12}\right)^2\)-x=y2
Bai 9: Tim x,y,z biet:
(x-1)2+(x+y)2+(xy-z)2=0