Question

tim x y biet 28(x-1)^2 + y ^2=37

Answer 1

Ta có: \(28\left(x-1\right)^2\)chẵn mà 37 lẻ nên \(y^2\)lẻ

Mà \(y^2\)là số chính phương và \(y^2\le37\)nên \(y^2\in\left\{1;9;25\right\}\)

\(TH1:y^2=1\Rightarrow\left(x-1\right)^2=\frac{36}{28}\left(L\right)\)

\(TH2:y^2=9\Rightarrow\left(x-1\right)^2=1\Rightarrow\orbr{\begin{cases}x=2\\x=0\end{cases}}\)

\(TH3:y^2=25\Rightarrow\left(x-1\right)^2=12\left(L\right)\)