\(->x^2+8x+16-x^2+1=0\\ ->8x+17=0->8x=-17\\ ->x=-\dfrac{17}{8}\)
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Bài 3: Những hằng đẳng thức đáng nhớ
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Tìm x: a)(2x+1)(1-2x)+(1-2x)^2=18
b) 2(x+1)^2-(x-3)(x+3)-(x-4)^2=0
c) (x-5)^2-x(x-4)=9
d) (x-5)^2+(x-4)(1-x)=0
Bài 3: Tìm x biết:
1, \(4x^2-36=0\)
2, \(\left(x-1\right)^2+x\left(4-x\right)=11\)
3, \(\left(x-5\right)^2-x.\left(x+2\right)=5\)
4, \(x\left(x+4\right)-x^2-6x=10\)
Tìm x biết
1.(x+3)2-(x+2).(x-2)=4x+17
2.(2x+1)2-(4x-1).(x-3)-15=0
3.(2x+3).(x-1)+(2x-3).(1-x)=0
4.2(5x-8)-3(4x-5)=4(3x-4)+11
5.(3x-1).(2x-7)-(1-3x).(6x-5)=0
2 tháng 10 2020 lúc 18:48
a)(2x-1)^2+(x+3)^2-5(x+7)(x-7)=0
b)(x+2)(x^2-2x+4)-x(x^2+2)=15
c)(x+3)^3-x(3x+1)^2+(2x-1)(4x^2-2x+1)=28
d)(x^2-1)^3-(x^4+x^2+1)(x^2-1)=0
Tìm x biết
a,(x+4)^2-(x+1)(x-1)=16
b,(2x-1)^2-(x+3)-5(x-7)(x+7)=0
c,3(x-1)^2-3x(x-5)=1
d,6(x-2)^2+(5x-2)^2-4(3x-1)(5x-2)=0
e,(x-2)^3-x^2(x-6)=4
g,(x-1)(x^2+x+1)-x(x+2)(x-2)=5
h,(x-1)^3-(x+3)(x^2-3x+9)+3(x^2-4)=2
Tìm x biết
1. 2(5x-8)-3(4x-5)=4(3x-4)+11
2. (2x+1)2-(4x-1).(x-3)-15=0
3. (3x-1).(2x-7)-(1-3x).(6x-5)=0
30 tháng 9 2020 lúc 20:04
a)(2x-1)^2+(x+3)^2-5(x+7)(x-7)=0
b)(x+3)^3-x(3x+1)^2+(2x-1)(4x^2-2x+1)=28
c)(x+2)(x^2-2x+4)-x(x^2+2)=15
d)(x^2-1)^3-x^4+x^2+1)(x^2-1)=0
Tìm x biết
1.x(x+1)-x2+1=0
2.4x.(x-2)-6+3x=0
3.x(x+2)-3(x+2)=0
Tìm x biết:
a) (x-1)(x^2+x+1) - x(x+2)(x-2) = 5
b) (6x-2)^2 + (5x-2)^2 - 4(3x-1)(5x-2) = 0
c) (x+1)^3 - x(x-2)^2 + x - 1 = 0
Tìm x, biết
a, 16x^2 - ( 4x-5)^2 = 15
b, (2x+3)^2 - 4(x-1)(x+1) = 49
c, (2x+1)(1-2x) + ( 1-2x)^3 =18
d, 2(x+1)^2 - ( x-3)(x+3) - (x
-4)^2 = 0
e, (x-5)^2 - x(x-4) = 9
f, ( x-5)^2 + ( x-4)(1-x) = 0
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