\(\left(x+3\right)\left(5x-20\right)=4-x\)
\(\Leftrightarrow5x^2-5x-60=4-x\)
\(\Leftrightarrow5x^2-4x-64=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=4\\x=-\frac{16}{5}\end{cases}}\)
P/s haphuong
Tim x
(x+3) x (5x-20) = 4-x
can gap
tim x thuoc Z biet |x-2| - 5(x-4) = 20 - 5x
bai 1 tim x biet;
1) 3x - 6 = 5x + 2
2) 15 - x =4x - 5
3) x - 15= 6 + 4x
4) -12 + x=5x - 20
5) 7x - 4 =20 + 3x
tim x biet
h x^2-7chia het x+3
k 3x^2+5x+8 chia het x+1
m 20 chia het x+1
p 2x+7chia het x-2
n 3x+8 chia het 5x-7
Tim x :x-2/4=5x/3
Tim x biet:|x2 -5x +4| = 5x-x-4
Tim x
10-2.x=25-3x
4.x-(3+5x)=14
|5x-12| < hoặc = 13
tim x
a, 5x-9=2x+15
b, 2 .(x-3)-4(x+4)=3.(-7) + 5
Tim x
|x+1|.(x-2)=2
5x+6y=48
|x|+3.|y|=4
