Question

tìm x : x^2-16=0

Answer 1

x² - 16 = 0

x² = 16

x = \(\left\{{}\begin{matrix}-4\\4\end{matrix}\right.\)

Answer 2

x^2-16=0

=> x^2-(4)^2=0

=> (x-4)(x+4)=0

nen x-4=0 hoac x+4=0

vay x=4 hoac x=-4

Answer 3

x\(^2\)-16=0

x\(^2\)-4\(^2\)=0

(x-4)(x+4)=0

⇒x-4=0 →x=4

x+4=0 →x=-4

Vậy x=4 hoặc x=-4

Answer 4

\(x^2-16=0\Leftrightarrow x^2-4^2=0\Leftrightarrow\left(x+4\right)\left(x-4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x+4=0\\x-4=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-4\\x=4\end{matrix}\right.\)