\(\frac{x-1}{-15}=\frac{-60}{x-1}\left(ĐK:x\ne1\right)\)
\(\Rightarrow\left(x-1\right)\left(x-1\right)=\left(-15\right)\left(-60\right)\\ \Rightarrow\left(x-1\right)^2=900\\ \Rightarrow\left[{}\begin{matrix}x-1=30\\x-1=-30\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=31\left(t/m\right)\\x=-29\left(t/m\right)\end{matrix}\right.\)
\(\text{Vậy }x\in\left\{31;-29\right\}\)
x-1/-15=-60/x-1
(x-1)²=-15×(-60)
(x-1)²=900
=>[x-1=30
[x-1=-30
=>[x=31
[x=-29
\(\frac{x-1}{-15}=\frac{-60}{x-1}\)
\(\Rightarrow\left(x-1\right).\left(x-1\right)=\left(-15\right).\left(-60\right)\)
\(\Rightarrow\left(x-1\right)^2=900\)
\(\Rightarrow\left(x-1\right)^2=\left(\pm30\right)^2\)
\(\Rightarrow x-1=\pm30.\)
\(\Rightarrow\left[{}\begin{matrix}x-1=30\\x-1=-30\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=30+1\\x=\left(-30\right)+1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=31\\x=-29\end{matrix}\right.\)
Vậy \(x\in\left\{31;-29\right\}.\)
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\(\frac{x-1}{-15}=\frac{-60}{x-1}\)
\(\Leftrightarrow\left(x-1\right)^2=900\)
\(\Leftrightarrow\left(x-1\right)^2=\left(\pm30\right)^2\)
\(\Rightarrow x-1\in\left\{30;-30\right\}\)
\(\Rightarrow\left\{{}\begin{matrix}x-1=30\\x-1=-30\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=31\\x=-29\end{matrix}\right.\)
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