Đặt \(\frac{x}{3}=\frac{y}{5}=k\)
Ta có: \(x=3k;y=5k\)
\(\Rightarrow xy=15k^2\)
\(\Rightarrow60=15k^2\)
\(\Rightarrow k^2=60:15=4\)
\(\Rightarrow k=2\)
\(\Rightarrow x=2.3=6\)
\(y=2.5=10\)
Vậy x = 6 và y = 10
Dat : \(\frac{x}{3}=\frac{y}{5}=k\)
\(\Rightarrow x=3k,y=5k\)
Do \(x\times y=60\)
nen \(3k.5k=60\Leftrightarrow15k^2=60\)
\(\Leftrightarrow k^2=4\Rightarrow\orbr{\begin{cases}k=2\\k=-2\end{cases}}\)
+) \(k=2\Rightarrow\hept{\begin{cases}x=6\\y=10\end{cases}}\)
+) \(k=-2\Rightarrow\hept{\begin{cases}x=-6\\y=-10\end{cases}}\)