Question

tìm x trong tỉ lệ thức:

a) (x-1)/(x+5)=6/7

b) x²/6=24/25

c) (x-2)/(x-1) = (x+4)/(x+7)(x khác 1,-7)

Answer 1

a)

 

b) \(\dfrac{x^2}{6}=\dfrac{24}{25}\)

\(\Leftrightarrow\left(5x\right)^2=144\)

\(\Leftrightarrow\left(5x\right)^2=12^2\)

\(\Leftrightarrow\left[{}\begin{matrix}5x=12\\5x=-12\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{12}{5}\\x=-\dfrac{12}{5}\end{matrix}\right.\)

c) \(\dfrac{x-2}{x-1}=\dfrac{x+4}{x+7}\)

\(\Leftrightarrow\left(x-2\right)\left(x+7\right)=\left(x-1\right)\left(x+4\right)\)

\(\Leftrightarrow x^2+5x-14=x^2+3x-4\)

\(\Leftrightarrow2x=10\)

\(\Leftrightarrow x=5\)