Question

Tìm x trong các hỗn số sau:

a, 4\(\frac{3}{x}\)=  \(\frac{47}{x}\)

b, x\(\frac{x}{15}\)= \(\frac{112}{5}\)

Uzumaki Naruto bn ten j z?  bn lop may va co phai quen mk ko?

 

Answer 1

\(a,4\frac{3}{x}=\frac{47}{x}\)

\(\frac{4x+3}{x}=\frac{47}{x}\)

\(\Rightarrow4x^2+3x=47x\)

\(4x^2=47x-3x=44x\)

\(4x^2:4x=44x:4x\)

\(x=11\)

\(b,x\frac{x}{15}=\frac{112}{5}\)

\(\frac{15x+x}{15}=\frac{112}{5}\)

\(75x+5x=112.15\)

\(80x=1680\)

\(x=21\)

Answer 2

a,        \(4\frac{3}{x}=\frac{47}{x}\)

   \(\Leftrightarrow\frac{4x+3}{x}=\frac{47}{x}\)

\(\Leftrightarrow4x+3=47\)

                \(4x=47-3\)

                \(4x=44\)

                  \(x=44:4\)

                  \(x=11\)

b,            \(x\frac{x}{15}=\frac{112}{5}\)

\(\Leftrightarrow\frac{15x+x}{15}=\frac{112}{5}\)

        \(\Leftrightarrow\frac{16x}{15}=\frac{336}{15}\)

          \(\Leftrightarrow16x=336\)

                       \(x=336:16\)

                       \(x=21\)