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k nha
\(B=\frac{x+2}{x-1}=\frac{\left(x-1\right)+3}{x-1}=1+\frac{3}{x-1}\)
Để \(B\inℤ\) thì \(3⋮x-1\) hay \(x-1\inƯ\left(3\right)=\left\{\pm1;\pm3\right\}\)
Nếu \(x-1=1\Rightarrow x=2\)
Nếu \(x-1=-1\Rightarrow x=0\)
Nếu \(x-1=3\Rightarrow x=4\)
Nếu \(x-1=-3\Rightarrow x=-2\)
Vậy \(B\inℤ\) khi \(x\in\left\{-2;0;2;4\right\}\)