tim x thuoc Z biet :
(x-1)^2 =(x-3)^4
HELP ME:0!!
Tim x, y thuoc Z biet : | x-2| + (x-y+1)^2 =0
tim x,y,z thuoc z biet /x/+/y/+/z/=0
cho P =|x|.(y-1).Tim x,y thuoc Z biet P<0
tim x thuoc Z biet (x-7)x(x+3)<0
Tim X thuoc Z biet :
(x-3).(x+2)<0
tim x thuoc z,biet
(x-5)^2=0
Tim x biet
(x-2)(x+3)<0 voi x thuoc z
tim x thuoc z biet
(x-1)(x-3)=-5
(x+1)(x+4)=0
(x^2-4)(x^2-19)<0