Question

Tìm x thuộc Q

a. \(\frac{13}{x-1}+\frac{5}{2x-2}-\frac{6}{3x-3}=3\) 

 

b. \(\frac{2x}{3}-\frac{3}{4}>0\)

Answer 1

Cau nay minh lam rui do !! Doi minh dang lam cau c va d   !!

Answer 2

a)\(\frac{13}{x-1}+\frac{5}{2\left(x-1\right)}-\frac{6}{3\left(x-1\right)}=3\)

\(\left(13+\frac{5}{2}-2\right)\left(\frac{1}{x-1}\right)=3\)

27/2*1/(x-1)=3

1/(x-1)=3:27/2

1/(x-1)=2/9

x-1=9/2

x=11/2

b)2x/3-3/4>0

2x/3>3/4

8x/12>9/12

=>8x>9 => x<=1