\(x^2+x=72\)
\(x^2+x-72=0\)
\(\left(x^2-8x\right)+\left(9x-72\right)=0\)
\(x\left(x-8\right)+9\left(x-8\right)=0\)
\(\left(x+9\right)\left(x-8\right)=0\)
\(\Rightarrow x-8=0\) (do \(x+9>0\) vì x thuộc N)
\(x=8\)
x2 + x = 72
x(2 + 1 ) = 72
x3 = 72
x = 72 : 3
x = 24