Question

Tìm x thuộc N biết 3^2x+ 3^2x+1= 324

Answer 1

\(3^{2x}+3^{2x+1}=324\)

\(\Rightarrow3^{2x}+3^{2x}.3=324\)

\(\Rightarrow3^{2x}\left(1+3\right)=324\)

\(\Rightarrow3^{2x}.4=324\)

\(\Rightarrow3^{2x}=324:4=81=3^4\)

\(\Rightarrow2x=4\)

\(\Rightarrow x=4:2=2\)

Answer 2

3^2x + 3^{2x + 1} = 324

=> 3^2x + 3^2x.3 = 324

=> 3^2x.(1 + 3) = 324

=> 3^2x.4 = 324

=> 3^2x = 324 : 4

=> 3^2x = 81

=> 3^2x = 3⁴

=> 2x = 4

=> x = 2

Answer 3

3^2x+3^2x+1=324

<=>3^2x+3^2x.3=324

<=>3^2x.(3+1)=324

<=>3^2x.4=324

<=>3^2x=81

<=>3^2x=3⁴

<=>2x=4

<=>x=2

vậy x=2

k mik nhé

hok tốt

Answer 4

3^2x+3^2x+1=324

<=>3^2x+3^2x.3=324

<=>3^2x.(3+1)=324

<=>3^2x.4=324

<=>3^2x=81

<=>3^2x=3⁴

<=>2x=4

=>x=2

vậy...

k mik nhé

!!!

Answer 5

3^2x + 3^{2x + 1} = 324

<=> 3^2x + 3^2x.3 = 324

<=> 3^2x.( 1 + 3 ) = 324

<=> 3^2x . 4 = 324

<=> 3^2x     = 324 : 4

<=>  3^2x    = 81

<=> 3^2x     = 3⁴

<=>  2x     = 4

<=>  x       = 2

Vậy x = 2

   !!!