16 chia hết cho (x-2)
=> \(\left(x-2\right)\inƯ\left(16\right)=\left\{1;2;4;8;16\right\}\)
=> \(x\in\left\{3;4;6;10;18\right\}\).
Nếu đã học số nguyên:
=> \(\left(x-2\right)\inƯ\left(16\right)=\left\{-16;-8;-4;-2;-1;1;2;4;8;16\right\}\)
=> \(x\in\left\{-14;-6;-2;0;1;3;4;6;10;18\right\}\)
16 chia het cho (x-2)=>x\(\in\)Ư(16)
Ư(16)\(\in\){1;2;4;8;16}
ta được
x-2=1 =>x=3
x-2=2 =>x=4
x-2=4 =>x=6
x-2=8 =>x=10
x-2=16 =>x=18