Các câu hỏi tương tự
Bài 1 : Tìm x biết :a, left|frac{3}{2}x+frac{1}{2}right|left|4x-1right|b, left|frac{5}{4}x-frac{7}{2}right|-left|frac{5}{8}x+frac{3}{5}right|0c,left|frac{7}{5}x+frac{2}{3}right|left|frac{4}{3}x-frac{1}{4}right|Bài 2 : Tìm x biết :a, | 2x - 5 | x +1 b, | 3x - 2 | -1 x c, | 3x - 7 | 2x + 1d, | 2x-1 | +1 x
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Bài 1 : Tìm x biết :
a, \(\left|\frac{3}{2}x+\frac{1}{2}\right|=\left|4x-1\right|\)
b, \(\left|\frac{5}{4}x-\frac{7}{2}\right|-\left|\frac{5}{8}x+\frac{3}{5}\right|=0\)
c,\(\left|\frac{7}{5}x+\frac{2}{3}\right|=\left|\frac{4}{3}x-\frac{1}{4}\right|\)
Bài 2 : Tìm x biết :
a, | 2x - 5 | = x +1
b, | 3x - 2 | -1 = x
c, | 3x - 7 | = 2x + 1
d, | 2x-1 | +1 = x
a) \(\frac{1}{20}\left(x-\frac{8}{15}\right)=\frac{-1}{30}\)
b) \(\left(28+\frac{1}{5}\right)\cdot\left(\frac{3}{5}\cdot x+\frac{4}{7}\right)=0\)
c)\(\left(x+3\right)\cdot\left(x-4\right)< 0\)
\(\left(\frac{1}{7}\cdot x-\frac{2}{7}\right)\cdot\left(-\frac{1}{5}\cdot x+\frac{3}{5}\right)\cdot\left(\frac{1}{3}\cdot x+\frac{4}{3}\right)=0\)
TÌM X
\(\left(\frac{1}{7}x-\frac{2}{7}\right)\cdot\left(-\frac{1}{5}x+\frac{3}{5}\right)\cdot\left(\frac{1}{3}x+\frac{4}{3}\right)=0\)
Tìm x:
\(a,\left(3\frac{1}{4}:x\right)\cdot\left(-1\frac{1}{4}\right)=-\frac{5}{3}-\frac{5}{6}\\ b,\left(-1\frac{1}{5}+x\right):\left(-3\frac{3}{5}\right)=-\frac{7}{4}+\frac{1}{4}:\frac{1}{8}\)
Tìm x:a) frac{3}{left(x+2right)cdotleft(x+5right)}+frac{5}{left(x+5right)cdotleft(x+10right)}+frac{7}{left(x+10right)cdotleft(x+17right)} frac{x}{left(x+2right)cdotleft(x+17right)}Với x không thuộc (-2;-5;-10;-17)b) frac{2}{left(x-1right)cdotleft(x-3right)}+frac{5}{left(x-3right)cdotleft(x-8right)}+frac{12}{left(x-8right)cdotleft(x-20right)}-frac{1}{20} frac{-3}{4}Với x không thuộc (1;3;8;20)c)frac{x+1}{2019}+frac{x+2}{2018} frac{x-3}{2017}frac{x-4}{2016}
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Tìm x:
a) \(\frac{3}{\left(x+2\right)\cdot\left(x+5\right)}\)+\(\frac{5}{\left(x+5\right)\cdot\left(x+10\right)}\)+\(\frac{7}{\left(x+10\right)\cdot\left(x+17\right)}\)= \(\frac{x}{\left(x+2\right)\cdot\left(x+17\right)}\)
Với x không thuộc (-2;-5;-10;-17)
b) \(\frac{2}{\left(x-1\right)\cdot\left(x-3\right)}\)+\(\frac{5}{\left(x-3\right)\cdot\left(x-8\right)}\)+\(\frac{12}{\left(x-8\right)\cdot\left(x-20\right)}\)-\(\frac{1}{20}\)= \(\frac{-3}{4}\)
Với x không thuộc (1;3;8;20)
c)\(\frac{x+1}{2019}\)+\(\frac{x+2}{2018}\)= \(\frac{x-3}{2017}\)\(\frac{x-4}{2016}\)
TÌM x
\(\left(\left(\frac{3}{4}\cdot x+5\right)-\left(\frac{2}{3}\cdot x-4\right)-\left(\frac{1}{6}\cdot x+1\right)\right)=\left(\frac{1}{3}\cdot x+4\right)-\left(\frac{1}{3}-3\right)\)
a)\(\left(\frac{5}{7}x-\frac{1}{4}\right)\left(\frac{-3}{4}x+\frac{1}{2}\right)=0\)
b)\(\left(\frac{4}{5}+x\right).\left(x-\frac{8}{13}\right)=0\)
c)\(\left(2x-\frac{1}{2}\right).\left(x-3\right)=0\)
d)\(x+3\frac{1}{2}x+x=\frac{1}{2}\)
TÌM X
a,\(\left(\frac{1}{7}x-\frac{2}{7}\right).\left(\frac{1}{5}x+\frac{3}{5}\right).\left(\frac{1}{3}x+\frac{4}{3}\right)=6\)
b,\(\left(x^2-4\right).\left(2x+\frac{4}{3}\right)=0\)