\(ĐK:x\ne\frac{-2}{3};x\ne3\)
\(\frac{6x-1}{3x+2}=\frac{2x+5}{x-3}\)
\(\Rightarrow\left(6x-1\right)\left(x-3\right)=\left(2x+5\right)\left(3x+2\right)\)
\(\Rightarrow6x^2-x-18x+3=6x^2+15x+4x+10\)
\(\Rightarrow-19x+3=19x+10\)
\(\Rightarrow38x=-7\Rightarrow x=\frac{-7}{38}\left(tm\right)\)
\(\frac{6x-1}{3x+2}=\frac{2x+5}{x-3}\)
<=> (6x-1)(x-3)=(2x+5)(3x+2)
<=> 6x2-18x-x+3=6x2+4x+15x+10
<=> 6x2-19x+3=6x2+19x+10
<=> 6x2-19x-19x-6x2=10-3
<=> -38x=7
<=> x=-7/38
Hai bạn kia làm đúng rồi ^v^
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