Question

Tìm x ở dạng lũy thừa

1/2.2^x+4.2^x=9.2^5

Mọi người giúp với ạ em cảm ơn

Answer 1

\(\frac{1}{2}2^x+4.2^x=9.2^5\)

\(\Leftrightarrow2^x\left(\frac{1}{2}+4\right)=9.2^5\)

\(\Leftrightarrow2^x\frac{9}{2}=9.2^5\)

\(\Leftrightarrow2^x\frac{9}{2}=288\)

\(\Leftrightarrow2^x=64\)

\(\Leftrightarrow2^x=2^6\)

\(\Rightarrow x=6\)

Answer 2

\(\frac{1}{2}.2^x+4.2^x=9.2^5\)

<=> \(2^x\left(\frac{1}{2}+4\right)=9.2^5\)

<=> \(2^x.\frac{9}{2}=9.2^5\)

<=> \(2^x=2^6\)

<=> x = 6

Answer 3

2^x.(1/2+4)=9.2^5

2^x.9/2=9.2^5

2^x.9/2=9.32

2^x.9/2=288

2^x=288:9/2

2^x=288.2/9

2^x=64

2^x=2^6

vậy x=6

Answer 4

     

      1/2 * 2^x + 4 * 2^x = 9 * 2^5

      1/2 * 2^x + 4 * 2^x = 288

      (1/2 + 4) * 2^x = 288

      4,5 * 2^x = 288

               2^x = 288 : 4,5

               2^x = 64

               2^x = 2^6

                    x = 6