\(2\left(4x-5\right)^2-4x+5=0\)
\(\Leftrightarrow2\left(4x-5\right)^2-\left(4x-5\right)=0\)
\(\Leftrightarrow\left(4x-5\right)\left(8x-10-1\right)=0\)
\(\Leftrightarrow\left(4x-5\right)\left(8x-11\right)=0\)
\(\Leftrightarrow\hept{\begin{cases}4x-5=0\\8x-11=0\end{cases}\Leftrightarrow\hept{\begin{cases}x=\frac{5}{4}\\x=\frac{11}{8}\end{cases}}}\)
2(4x-5)^2 -4x+5 =0
(8x-10)(4x-5)-(4x-5) =0
(8x-11)(4x-5)=0
Suy ra: (8x-11)(4x-5) =0
Do đó: 8x-11=0 hoặc 4x-5=0
x=11/8 hoặc x=5/4
Vậy x=11/8 hoặc x=5/4
\(2\left(4x-5\right)^2-4x+5=0\)
\(\Leftrightarrow\)\(\left(4x-5\right)\left[2\left(4x-5\right)-1\right]=0\)
\(\Leftrightarrow\)\(\left(4x-5\right)\left(8x-11\right)=0\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}4x-5=0\\8x-11=0\end{cases}}\)
\(\Leftrightarrow\)\(\orbr{\begin{cases}x=\frac{5}{4}\\x=\frac{11}{8}\end{cases}}\)
Vậy...
