Question

Tìm x: \(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)

Answer 1

x *4+1/2+1/4+1/8+1/16=1.

từ đó ra

Answer 2

x. 4 +15/16 = 1

x.4 = 1 - 15/16 = 1/16

x = 1/16 : 4 = 1/64

 

Answer 3

\(x+\frac{1}{2}+x+\frac{1}{4}+x+\frac{1}{8}+x+\frac{1}{16}=1\)

\(4\cdot x+\frac{1+2+4+8}{16}=1\)

\(4\cdot x+\frac{15}{16}=1\)

Vậy 4*x = 1 - 15/16 = 1/16

Nên x = \(\frac{1}{16}:4=\frac{1}{64}\)

Answer 4

x*4+1/2+1/4+1/8+1/16=1

x*4+15/16=1

x*4=1-15/16

x*4=1/16

x=1/16:4=1/64