\(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=5750\)
\(\left(x\cdot100\right)+\left(1+2+...+100\right)=5750\)
\(\left(x\cdot100\right)+\left(100+1\right)\cdot\frac{100}{2}=5750\)
\(\left(x\cdot100\right)+101\cdot50=5750\)
\(\left(x\cdot100\right)+5050=5750\)
\(x\cdot100=5750-5050\)
\(x\cdot100=700\)
\(x=700\div100\)
\(x=7\)
Ta có: ( x+1)+(x+2)+(x+3)+.....+(x+99)+(x+100)=5750
<=>(x+x+x+....+x+x)+(1+2+3+..+99+100)=5750
<=> 100x+5050=5750
=>100x=5750-5050
=>100x=700
=>x=700:100
=>x=7
Vậy x=7
hoặc mở câu hỏi tương tự tham khảo.
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\)
\(\Leftrightarrow100x+\left(1+2+3+...+100\right)=5750\)
\(\Leftrightarrow100x+\left(100+1\right)\times100\div2=5750\)
\(\Leftrightarrow100x+101\times50=5750\)
\(\Leftrightarrow100x=700\)
\(\Leftrightarrow x=7\)
mày là star boyvn thì tao là as mobile
