\(\left|x-\frac{1}{3}\right|=\left|2-3x\right|\)
\(\Leftrightarrow\left[{}\begin{matrix}x-\frac{1}{3}=2-3x\\x-\frac{1}{3}=-\left(2-3x\right)\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\frac{7}{12}\\x=\frac{5}{6}\end{matrix}\right.\)
Vậy \(x\in\left\{\frac{7}{12};\frac{5}{6}\right\}\)
Chúc bạn may mắn !
\(\left|x-\frac{1}{3}\right|=\left|2-3x\right|\)
\(\Rightarrow\left|x-\frac{1}{3}\right|=2-3x.\)
\(\Rightarrow\left[{}\begin{matrix}x-\frac{1}{3}=2-3x\\x-\frac{1}{3}=3x-2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x+3x=2+\frac{1}{3}\\x-3x=-2+\frac{1}{3}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}4x=\frac{7}{3}\\-2x=-\frac{5}{3}\end{matrix}\right.\)
\(\Rightarrow\left[{}\begin{matrix}x=\frac{7}{3}:4\\x=\left(-\frac{5}{3}\right):\left(-2\right)\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{7}{12}\\x=\frac{5}{6}\end{matrix}\right.\)
Vậy \(x\in\left\{\frac{7}{12};\frac{5}{6}\right\}.\)
Chúc bạn học tốt!
