Bài 1:
a) \(\left(2-3x\right)-\left(5x+8\right)=15x\)
\(\Leftrightarrow2-3x-5x-8-15x=0\)
\(\Leftrightarrow-23x-6=0\)
\(\Leftrightarrow x=\frac{-6}{23}\)
Vậy...
b) \(3\left(x-3\right)-2\left(8-x\right)=6\)
\(\Leftrightarrow3x-9-16+2x-6=0\)
\(\Leftrightarrow5x-31=0\)
\(\Leftrightarrow x=\frac{31}{5}\)
Vậy...
c) \(\frac{7-x}{2}-\frac{2x-3}{4}=\frac{x+2}{8}-\frac{-1}{2}\)
\(\Leftrightarrow4\left(7-x\right)-2\left(2x-3\right)=x+2+4\)
\(\Leftrightarrow28-4x-4x+6-x-6=0\)
\(\Leftrightarrow-9x+28=0\)
\(\Leftrightarrow x=\frac{28}{9}\)
Vậy...
d) \(x^2\cdot\left(-4x\right)+3=0\)
\(\Leftrightarrow-4x^3=-3\)
\(\Leftrightarrow x^3=\frac{3}{4}\)
\(\Leftrightarrow x=\sqrt[3]{\frac{3}{4}}\)
Vậy...
a) \(\left(2-3x\right)-\left(5x+8\right)=15x\)
\(\Leftrightarrow2-3x-5x-8=15x\)
\(\Leftrightarrow15x+3x+5x=2-8\)
\(\Leftrightarrow23x=-6\)
\(\Leftrightarrow x=-\frac{6}{23}\)
Vậy : \(x=-\frac{6}{23}\)
b) \(3\left(x-3\right)-2\left(8-x\right)=6\)
\(\Leftrightarrow3x-9-16+2x=6\)
\(\Leftrightarrow5x=6+9+16=41\)
\(\Leftrightarrow x=\frac{41}{5}\)
Vậy : \(x=\frac{41}{5}\)
Bài 1:
a) \(\left(2-3x\right)-\left(5x+8\right)=15x\)
=> \(2-3x-5x-8=15x\)
=> \(15x+3x+5x=2-8\)
=> \(23x=-6\)
=> \(x=\left(-6\right):23\)
=> \(x=-\frac{6}{23}\)
Vậy \(x=-\frac{6}{23}.\)
Mình chỉ làm câu a) thôi nhé.
Chúc bạn học tốt!
a, (2 - 3x) - (5x+8) =15x ⇔2 -3x - 5x -8 =15x
⇔ -6- 8x =15x
⇔ -23x= 6
⇔x = -6/23
b,3(x-3) - 2(8 - x) = 6
⇔3x - 9 - 16 +2x = 6
⇔5x = 31
⇔x = 31/5
c, 7 - x /2 - 2x - 3 /4 = x+2/8= -1/2
⇔28-4x - 4x + 6 = x + 2 =-4
⇔-9x = -28
⇔x = 28/9
d, x∈∅ vì -4x3≠-3
a, (2−3x)−(5x+8)=15x
<=> 2 - 3x - 5x - 8 =15x
<=> -6 - 8x = 15x
<=> -6 = 15x + 8x
<=> -6 = 23x
<=> x = \(\frac{-23}{6}\)
Vậy x = \(\frac{-23}{6}\).
b, 3(x−3)−2(8−x)=6
<=> 3x - 9 - 16 +2x = 6
<=> 5x - 25 = 6
<=> 5x = 31
<=> x = \(\frac{31}{5}\)
Vậy x = \(\frac{31}{5}\).
